8+(x+3)^2=x(x-6)-7

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Solution for 8+(x+3)^2=x(x-6)-7 equation: 



8+(x+3)^2=x(x-6)-7

We move all terms to the left:

8+(x+3)^2-(x(x-6)-7)=0



We calculate terms in parentheses: -(x(x-6)-7), so:

x(x-6)-7

We multiply parentheses

x^2-6x-7

Back to the equation:

-(x^2-6x-7)



We get rid of parentheses

-x^2+(x+3)^2+6x+7+8=0

We add all the numbers together, and all the variables

-1x^2+6x+(x+3)^2+15=0

We move all terms containing x to the left, all other terms to the right

-1x^2+6x+(x+3)^2=-15

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